(((6x^2)-21x-291)/((x^2)-4x-25))=6

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Solution for (((6x^2)-21x-291)/((x^2)-4x-25))=6 equation: 



(((6x^2)-21x-291)/((x^2)-4x-25))=6

We move all terms to the left:

(((6x^2)-21x-291)/((x^2)-4x-25))-(6)=0



Domain of the equation: (x^2-4x-25))!=0

x∈R



We multiply all the terms by the denominator


((6x^2-21x-291)-6*(x^2-4x-25))=0



We calculate terms in parentheses: +((6x^2-21x-291)-6*(x^2-4x-25)), so:

(6x^2-21x-291)-6*(x^2-4x-25)

We multiply parentheses

-6x^2+(6x^2-21x-291)+24x+150

We get rid of parentheses

-6x^2+6x^2-21x+24x-291+150

We add all the numbers together, and all the variables

3x-141

Back to the equation:

+(3x-141)



We get rid of parentheses

3x-141=0

We move all terms containing x to the left, all other terms to the right

3x=141

x=141/3

x=47

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